(A/s) Biology May/June 2022 paper 3 variant 2
Question paper found on page 8 / 16 pages total, pdf
8 (ii) Suggest an explanation for the results for a daily dose of 0 mg and the results for daily doses of between 500–1000 mg. 0 mg ......................................................................................
(A/s) Biology Oct/Nov 2018 paper 1 variant 3
Question paper found on page 17 / 20 pages total, pdf
17 38 Which graph shows the changes in antibody concentration following a second exposure to the same infection? 1000 A antibody concentration / arbitrary units 100 10 1 0 10 20 30 40 50 60 70 80 time / days first exposure second exposure 1000 B antibody concentration / arbitrary units 100 10 1 0 10 20 30 40 50 60
(A/s) Biology Oct/Nov 2005 paper 6
Question paper found on page 2 / 36 pages total, pdf
2 9700/06/O/N/05 OPTION 1 – MAMMALIAN PHYSIOLOGY 1 (a) Fig. 1.1 is a photomicrograph of compact bone. × 1000 Fig. 1.1 © UCLES 2005 D A B C
(A/s) Biology May/June 2021 paper 1 variant 3
Question paper found on page 2 / 20 pages total, pdf
2 1 2 Which set of measurements is correct? diameter of capillarydiameter of red blood cellthickness of cell surface membrane of red blood cell A7 m7 m7 nm B7 m7 nm7 nm C0.7 mm7 m7 nm D0.7 mm0.7 mm7 m The diagram shows an eyepiece graticule and part of a stage micrometer scale as seen using 100 magnification. eyepiece graticule stage
(A/s) Biology May/June 2017 paper 1 variant 3
Question paper found on page 2 / 20 pages total, pdf
2 1 Where are cisternae found in a cell? A 2 1 endoplasmic reticulum 2 Golgi body 3 mitochondrion 1 and 2 B 1 and 3 C 1 only D 2 and 3 The diagram shows an eyepiece graticule and part of a stage micrometer scale as seen using ×100 magnification. eyepiece graticule stage micrometer scale 0.1 mm How is the value, in µm, of one eyepiece graticule unit calculated?
(A/s) Biology May/June 2017 paper 1 variant 1
Question paper found on page 3 / 20 pages total, pdf
3 4 Which lengths are equivalent to 1 µm? A 5 1 1000 mm 2 0.001 nm 3 0.001 mm 4 1 000 000 nm 5 0.01 mm 6 1000 nm 1 and 4 B 2 and 5 C 3 and 4 D 3 and 6 Some secretory cells synthesise and release glycoproteins. What is the correct order of the sequence of events
(A/s) Biology May/June 2017 paper 5 variant 2
Question paper found on page 10 / 12 pages total, pdf
10 3 An investigation was carried out into the population of a species of vole in one area of the USA. The population was sampled during the first two weeks of August between 1983 and 2004. Traps for catching small mammals were placed at equal distances along the same parallel line transects. Each year, the number of voles caught per 1000 traps was recorded. Fig. 3.1
(A/s) Biology May/June 2010 paper 3 variant 5
Mark scheme found on page 8 / 9 pages total, pdf
Page 8 Mark Scheme: Teachers’ version Syllabus Paper GCE AS/A LEVEL – May/June 2010 9700 35 © UCLES 2010 Question Expected Answers Additional Guidance Marks (iii) Calculate the actual distance across the lumen of the structure shown by line X in Fig. 2.1. MMO collection 1 measures line X correctly in mm or cm Reject m [1] shows their measurement divided by or
(A/s) Biology May/June 2012 paper 4 variant 2
Question paper found on page 17 / 28 pages total, pdf
17 9700/42/M/J/12 © UCLES 2012 [Turn over For Examiner’s Use (b) Plant biodiversity varies throughout the world and is dependent on many factors, particularly climate. Fig. 6.1 shows the relationship between the number of plant genera and the mean annual rainfall in seven countries. 0 0 1000 2000 3000 500 1000 1500 mean
(A/s) Biology Oct/Nov 2019 paper 3 variant 5
Mark scheme found on page 8 / 8 pages total, pdf
9700/35 Cambridge International AS/A Level – Mark Scheme PUBLISHED Question 2(b)(i) Answer anaphase ; October/November 2019 Marks 2 chromatids have separated and moved towards the poles ; 2(b)(ii)3 or 4 ;1 2(b)(iii)mp1 correct measurement of line R + units ;4 mp2 mp3 conversion of line Rconversion of actual cell Q length (mm) shows (whatever measurement
(A/s) Biology Feb/March 2021 paper 4 variant 2
Question paper found on page 5 / 28 pages total, pdf
5 (b) Grey wolves can have territories of up to 950 km2. Grey wolves can travel up to 1000 km to start a new population. State reasons why the mark-release-recapture method is not suitable for estimating the size of a grey wolf population. .................................................
(A/s) Biology May/June 2009 paper 3 variant 1
Mark scheme found on page 7 / 9 pages total, pdf
Page 7 Mark Scheme: Teachers’ version Syllabus Paper GCE A/AS LEVEL – May/June 2009 9700 31 © UCLES 2009 divides by 400 and multiplies by (cm) 10 000/10 4 or (mm) 1000/10 3 ; E.g. cell 1 = 20 mm cell 2 = 21 mm cell 3 = 17 mm cell 4 = 16 mm
(A/s) Biology May/June 2021 paper 3 variant 4
Mark scheme found on page 7 / 7 pages total, pdf
9700/34Cambridge International AS & A Level – Mark Scheme PUBLISHED QuestionAnswer May/June 2021 Marks 2(c)(i)1 2 3division of 0.8 mm by 40 ; multiplies answer in mm by 1000 (to convert to μm) ; correct answer with appropriate units ;3 2(c)(ii)83 eyepiece graticule units ; shows 83 multiplied by the answer from Question 2(c)(
(A/s) Biology May/June 2010 paper 3 variant 3
Mark scheme found on page 11 / 13 pages total, pdf
Page 11 Mark Scheme: Teachers’ version Syllabus Paper GCE AS/A LEVEL – May/June 2010 9700 33 © UCLES 2010 Question Expected Answers Additional Guidance Marks (iii) Calculate the actual diameter of the cell shown by the line X in Fig. 2.2. measures line X correctly in mm or cm; Reject m mm cm 26(.0) 2.6 26.5 2.65
(A/s) Biology May/June 2009 paper 3 variant 2
Mark scheme found on page 9 / 10 pages total, pdf
Page 9 Mark Scheme: Teachers’ version Syllabus Paper GCE A/AS LEVEL – May/June 2009 9700 32 © UCLES 2009 (b) Calculate the area of view. Count and record no. of stomata in field of view. Calculate no. of stomata per mm 2 . PDO display 1 MMO collection 1 MMO decision 1 MMO collection 1 PDO display 1 calculation of field of view shown;
(A/s) Biology May/June 2010 paper 3 variant 1
Mark scheme found on page 7 / 9 pages total, pdf
Page 7 Mark Scheme: Teachers’ version Syllabus Paper GCE AS/A LEVEL – May/June 2010 9700 31 © UCLES 2010 Question Expected Answers Additional Guidance Marks (b) (i) Calculate the actual length, shown by line X, of one of the structures. measures line X correctly in mm or cm; Reject m mm cm 54.(0) 5.4 54.5 5.45 5
(A/s) Biology May/June 2010 paper 5 variant 1
Question paper found on page 5 / 12 pages total, pdf
5 9700/51/M/J/10 © UCLES 2010 [Turn over For Examiner’s Use Fig. 1.3 shows the results that the student plotted from the investigation. 0 0 x -axis y -axis 500 1000 1500 2000 shade leaves sun leaves Fig. 1.3 (b) (i) Suggest labels for the axes of this graph. x-axis ......
(A/s) Biology May/June 2011 paper 3 variant 5
Mark scheme found on page 10 / 11 pages total, pdf
Page 10 Mark Scheme: Teachers’ version Syllabus Paper GCE AS/A LEVEL – May/June 2011 9700 35 © University of Cambridge International Examinations 2011 (ii) Use the scale bar to calculate the magnification of Fig. 2.2. [4] measures scale bar in mm; 14 or 14.5 or 15 or 15.5 or 16 mm MMO collection 1 [1] Additional guidance
(A/s) Biology Feb/March 2022 paper 4 variant 2
Question paper found on page 19 / 28 pages total, pdf
19 (i) With reference to Fig. 6.2, describe and explain the results at a light intensity of 1000 lux. .....................................................................................................
(A/s) Biology May/June 2008 paper 3 variant 2
Mark scheme found on page 7 / 9 pages total, pdf
Page 7 Mark Scheme Syllabus Paper GCE A/AS LEVEL – May/June 2008 9700 32 (ii) Use this information to calculate the actual width of the vascular bundle. 2 MMO collection, 1 PDO recording, 1 PDO display [4] How to mark the calculation. Step 1 : W (1) X Y Z Step 2 : Calculate the answer USING their figures (Z/Y × X ×
(A/s) Biology May/June 2011 paper 2 variant 1
Question paper found on page 15 / 16 pages total, pdf
15 9700/21/M/J/11 © UCLES 2011 For Examiner’s Use 0 0 50 100 150 200 250 300 10 20 30 40 50 60 70 80 90 100 percentage of districts in each country vaccinating 90% of children against measles mortality rate of children under 5 years of age / deaths per 1000 children
(A/s) Biology May/June 2002 paper 6
Question paper found on page 10 / 24 pages total, pdf
10 9700/6/M/J/02 2 (a) Glucose biosensors can be made in many different ways by using the enzyme glucose oxidase. Suggest two methods that could be used to measure the glucose concentration. 1. ....................................................................
(A/s) Biology May/June 2011 paper 4 variant 2
Question paper found on page 12 / 24 pages total, pdf
12 © UCLES 2011 9700/42/M/J/11 For Examiner’s Use (ii) Explain how the leaf anatomy of a maize plant reduces photorespiration, even in hot, dry conditions. ............................................................................
(A/s) Biology Oct/Nov 2016 paper 3 variant 1
Mark scheme found on page 6 / 6 pages total, pdf
Page 6 Mark Scheme Syllabus Paper Cambridge International AS/A Level – October/November 2016 9700 31 © UCLES 2016 Question Answer Mark 2(c)(iii) (depth of midrib) 1 shows answer to (c)(i) multiplied by answer to (c)(ii) ; 2 decision to multiply by 1000 (to convert to μ m) ; 2 2(c)(iv) (improvements) 1 reference
(A/s) Biology Oct/Nov 2022 paper 2 variant 3
Question paper found on page 9 / 16 pages total, pdf
9 1600 1400 1200 1000 PAR / μmol m–2 s–1 800 600 400 200 0 12:00 24:0012:0024:0012:00 24:0012:0024:0012:00 24:0012:00 time of day24:0012:00 3.5 3.0 2.5 wind speed / m
(A/s) Biology May/June 2005 paper 6
Question paper found on page 19 / 36 pages total, pdf
19 9700/06/M/J/05 [Turn over (b) Fig. 4.1 shows part of a haemocytometer grid. The chamber contains a sample of yeast cells from beer A which has been diluted 1000 times. The large squares, with the double lines, measure 0.2 mm × 0.2 mm with a depth of 0.1 mm. Fig. 4.2 Calculate the total number of cells
(A/s) Biology May/June 2018 paper 3 variant 4
Mark scheme found on page 7 / 7 pages total, pdf
9700/34 Cambridge International AS/A Level – Mark Scheme PUBLISHED Question 2(c)(ii) Answer B1 walls thicker than B2 ; May/June 2018 Marks 3 B1 innermost layer is crinkled, B2 innermost layer smooth ; B2 has a larger lumen than B1 ; 2(c)(iii) B1 + thick(er) wall / more muscle tissue / AW ; 1 2(c)(iv)
(A/s) Biology May/June 2020 paper 3 variant 2
Mark scheme found on page 9 / 9 pages total, pdf
9700/32 Cambridge International AS & A Level – Mark Scheme PUBLISHED Question 2(c)(i) Answer 1 2 3 4 2(c)(ii) © UCLES 2020 records measured length of line Z ; A suitable range of measurements based on printed diagram shows mm and converts to μm by multiplying by 1000 and shows division by magnification (× 200) ; appropriate units for final answer
(A/s) Biology May/June 2012 paper 1 variant 2
Question paper found on page 7 / 20 pages total, pdf
7 © UCLES 2012 9700/12/M/J/12 [Turn over 15 The following are all processes by which substances can enter a cell. 1 endocytosis 2 facilitated diffusion 3 osmosis Which processes are passive? A 2 only B 3 only C 2 and 3 only D 1, 2 and 3 16 The diagram shows the water potential of three adjacent plant cells. –1200 kPa –
(A/s) Biology May/June 2011 paper 4 variant 3
Question paper found on page 12 / 24 pages total, pdf
12 © UCLES 2011 9700/43/M/J/11 For Examiner’s Use (ii) Explain how the leaf anatomy of a maize plant reduces photorespiration, even in hot, dry conditions. ............................................................................
(A/s) Biology May/June 2016 paper 1 variant 2
Question paper found on page 2 / 16 pages total, pdf
2 © UCLES 2016 9700/12/M/J/16 1 A student was presented with a photomicrograph of a cell organelle. The magnification of the photomicrograph is known. Which calculation of the actual length of the organelle in μ m is correct? A actual size in cm × 100 divided by the magnification B actual size in mm × 100 divided by the magnification C image size in
(A/s) Biology Feb/March 2023 paper 5 variant 2
Question paper found on page 15 / 20 pages total, pdf
15 State two conclusions that can be made from the data shown in Fig. 2.3. ...................................................................................................................
(A/s) Biology Oct/Nov 2019 paper 1 variant 3
Question paper found on page 2 / 20 pages total, pdf
2 1 Plant cells are stained and then seen with a simple light microscope using daylight as the only light source. Which cell structures are clearly visible at a magnification of ×400? 2 Achloroplast grana Blysosomes Cnucleoli Dribosomes How many nanometres are there in one millimetre? A 3 1000 B 10 000 C 100 000 D1 000 000 D2 and 4 only Which cell
(A/s) Biology May/June 2004 paper 6
Question paper found on page 11 / 36 pages total, pdf
11 9700/06/M/J04 [Turn over For Examiner’s Use © UCLES 2004 (c) Describe precisely how viruses multiply in the human body. ........................................................................................
(A/s) Biology May/June 2011 paper 3 variant 1
Mark scheme found on page 17 / 20 pages total, pdf
Page 17 Mark Scheme: Teachers’ version Syllabus Paper GCE AS/A LEVEL – May/June 2011 9700 31 © University of Cambridge International Examinations 2011 Expected Answers Mark (c) The actual length of line Y is 785 μ m. Use this measurement to calculate the magnification of Fig. 2.3 [3] measures line Y in mm; 22 22.5 23 23.5
(A/s) Biology Oct/Nov 2014 paper 4 variant 3
Question paper found on page 10 / 24 pages total, pdf
10 9700/43/O/N/14 © UCLES 2014 The results are shown in Fig. 4.2. 0 50 100 150 200 250 300 350 400 450 500 HB8 HB8 mutant flask 4 flask 5 separate cultures HB8 HB8 mutant flask 6 mixed culture 0 100 200 300 400 500 600 number
(A/s) Biology May/June 2020 paper 3 variant 2
Question paper found on page 9 / 16 pages total, pdf
9 (iii) Fig. 1.4 is a calibration curve of sucrose concentration against water potential. –4000 –3500 –3000 –2500 water potential / kPa –2000 –1500 –1000 –500 0 0 0.20 0.40 0.60 0.80 1.00 concentration of sucrose solution / mol dm–3 Fig. 1.4 Use the graphs in Fig
(A/s) Biology May/June 2018 paper 2 variant 2
Mark scheme found on page 5 / 18 pages total, pdf
9700/22 Cambridge International AS/A Level – Mark Scheme PUBLISHED Question 1(a) Answer one mark for each label to correct structure on Fig. 1.1 ; ; ; tonoplast line to anywhere on the vacuolar membrane May/June 2018 Marks 3 R if two or more different structures stated for a single label 1(b) ref. to conversion of measured (X-Y) line to µm /
(A/s) Biology Feb/March 2023 paper 1 variant 2
Question paper found on page 2 / 16 pages total, pdf
2 1 The photomicrograph shows cells from a human blood smear. neutrophil P Q Which calculation shows a correct method to calculate the actual diameter of the neutrophil shown in the photomicrograph in micrometres (m)? 2 Alength of line PQ in mm 1000 magnification of photomicrograph Blength of line PQ in mm 10 000 magnification of photomicrograph Cmagnification of photomicrograph length of line PQ in mm 1
(A/s) Biology Oct/Nov 2020 paper 4 variant 2
Question paper found on page 4 / 24 pages total, pdf
4 (ii) C4 plants have higher rates of photosynthesis than C3 plants when the ratio of atmospheric oxygen to atmospheric carbon dioxide is high. Fig. 1.2 shows the atmospheric carbon dioxide concentration in the last 50 million years. 1000 atmospheric 800 carbon dioxide / parts per million 600 400 200 0 40 30 20 10 0 50 time before present / million
(A/s) Biology Feb/March 2023 paper 5 variant 2
Question paper found on page 11 / 20 pages total, pdf
11 6000 5000 treatment 1: gamma radiation only 4000 mean acrylamide concentration 3000 / μg kg–1 2000 treatment 2: gamma radiation and hot water 1000 0 0 25 50 75 100 gamma radiation dose / J kg–1 125 150 Fig. 1.5 The scientists concluded that a combination of gamma radiation and hot water treatment is the
(A/s) Biology May/June 2017
Examiner report found on page 1 / 59 pages total, pdf
Cambridge International Advanced Subsidiary and Advanced Level 9700 Biology June 2017 Principal Examiner Report for Teachers BIOLOGY Paper 9700/11 Multiple Choice Question Number 1 2 3 4 5 D C C D B Question Number 21 22 23 24 25 6 7 8 9 10 A D D D D 26 27 28 29 30 D D C A A 11 12 1
(A/s) Biology Oct/Nov 2004 paper 6
Question paper found on page 18 / 36 pages total, pdf
18 9700/06/O/N/04 4 (a) P enicillin is produced in batch fermenters. Explain how a batch fermenter differs from a continuous fermenter. ..........................................................................................
(A/s) Biology Oct/Nov 2006 paper 4
Question paper found on page 6 / 16 pages total, pdf
3 In mammalian kidneys, the loop of Henle is closely associated with the process of osmoregulation. (a) Explain what is meant by osmoregulation. ...................................................................................................
(A/s) Biology Oct/Nov 2002 paper 2
Question paper found on page 6 / 12 pages total, pdf
6 9700/2/O/N/02 3 (a) Explain why transpiration is the inevitable consequence of gaseous exchange in land plants. .....................................................................................................
(A/s) Biology Feb/March 2020 paper 4 variant 2
Question paper found on page 18 / 28 pages total, pdf
18 (b) There were estimated to be about 300 000 sea otters in the year 1700. • • Extensive hunting for their fur resulted in the numbers of sea otters falling to about 1000 by the year 1911, when most hunting was banned. The population size then increased to about 125 000 by the year 2012. All of the sea otters alive
(A/s) Biology May/June 2011 paper 3 variant 4
Mark scheme found on page 11 / 12 pages total, pdf
Page 11 Mark Scheme: Teachers’ version Syllabus Paper GCE AS/A LEVEL – May/June 2011 9700 34 © University of Cambridge International Examinations 2011 Additional guidance Ignore • tick and cross without a key • diagrams • 3-D descriptions such as spherical • colours/staining (ii) Actual length of line Y is 495 μm. Use this to calculate the magnification of Fig.2.2
(IGCSE) Computer Science Oct/Nov 2015 paper 1 variant 3
Question paper found on page 6 / 16 pages total, pdf
6 3 A section of computer memory is shown below: Address Contents 1000 0000 0110 1110 1000 0001 0101 0001 1000 0010 1000 1101 1000 0011 1000 1100 1000 1100 1000 1101 1000 1110 1000 1111 (a) (
(A/s) Biology Oct/Nov 2008 paper 2
Mark scheme found on page 3 / 12 pages total, pdf
Page 2 Mark Scheme Syllabus Paper GCE A/AS LEVEL – October/November 2008 9700 02 © UCLES 2007 1 (a) check column A and B for correct ref. to feature if not clear in first column e.g. gives description feature phagocyte ( A ) plasma cell ( B ) rough endoplasmic reticulum / R ER allow ER if rough / RER stated in next column(s)
(IGCSE) Computer Science Oct/Nov 2015 paper 1 variant 3
Question paper found on page 7 / 16 pages total, pdf
7 (iii) Show any changes to the computer memory following the read and write operations in part (a)(i) and part (a)(ii). Address Contents 1000 0000 0110 1110 1000 0001 0101 0001 1000 0010 1000 1101 1000 0011 1000 1100 1000 1100 1
(A/s) Biology Oct/Nov 2009 paper 5 variant 2
Mark scheme found on page 6 / 7 pages total, pdf
Page 6 Mark Scheme: Teachers’ version Syllabus Paper GCE A/AS LEVEL – October/November 2009 9700 52 © UCLES 2009 Question Expected answer Extra guidance Mark AO (b) (i) If the total number of pollen grains is correct and the volume of air is correct from a calculation, give both marks. Allow any method of calculation that give the expected values. Calculations of values e
(A/s) Accounting Oct/Nov 2010 paper 4 variant 2
Mark scheme found on page 4 / 5 pages total, pdf
Page 4 3 Mark Scheme: Teachers’ version GCE A/AS LEVEL – October/November 2010 Syllabus 9706 Paper 42 (a) $ Revenue working 1 1 715 610 purchase cost (200 000) (1) salary (30 000 + 36 000 + 43 200 + 51 840 + 62 208) rent (3600 + 3600 +
(A/s) Biology Feb/March 2017 paper 3 variant 3
Mark scheme found on page 5 / 5 pages total, pdf
9700 / 33 Cambridge International AS/A Level – Mark Scheme PUBLISHED Question 2(b)(ii) 2(b)(iii) March 2017 Answer Marks (calculation of magnification) 4 1 measures length of line Z + units ; 2 shows multiplication of length of line Z (mm) by 1000 to convert to µm ; 3 shows division of length of line Z by 4500 ; 4
(A/s) Biology Feb/March 2018 paper 4 variant 2
Question paper found on page 10 / 28 pages total, pdf
10 (c) After cutting with Mst II, the DNA fragments are separated by gel electrophoresis. Explain how gel electrophoresis separates DNA fragments cut with restriction endonucleases. ............................................................................................
(A/s) Biology Oct/Nov 2012 paper 3 variant 5
Mark scheme found on page 8 / 10 pages total, pdf
Page 8 Mark Scheme Syllabus Paper GCE AS/A LEVEL – October/November 2012 9700 35 © Cambridge International Examinations 2012 labels lumen with label line into the space below innermost line; mp 4 Ignore Do not give if • any labels identifying tissues associated with animal • label is written between the innermost and outermost lines • any label which is biologically incorrect e.g. plant • any
(A/s) Biology Oct/Nov 2017 paper 4 variant 1
Question paper found on page 8 / 24 pages total, pdf
8 (c) Table 2.1 shows the results of the experiment. Table 2.1 colour of filter wavelength of light / nm time taken to decolourise DCPIP / s rate of light dependent stage of photosynthesis / s –1 purple 425 37 27.0 blue 450 84 11.9 green 525 480 2.1 orange 625 45 red 675 50 (i) 20.0
(A/s) Biology Oct/Nov 2022 paper 1 variant 1
Question paper found on page 2 / 16 pages total, pdf
2 1 The photomicrograph shows part of a plant cell. 5 μm What is the magnification of the cell? ×250 A 2 B ×400 C ×1000 D ×4000 Which row matches each organelle with its function? microtubules rough endoplasmic reticulum Golgi bodycentrioles Amake cilia and spindleseparates some processes from cytoplasmmakes lysosomesassemble the spindle during nuclear division Bmove vesicles within the cellassembles amino acids to make proteinscontains
(A/s) Biology May/June 2022 paper 4 variant 2
Question paper found on page 16 / 28 pages total, pdf
16 (c) The germination of three groups of seeds of the plant Penstemon digitalis was investigated. The seeds were soaked for 24 hours in distilled water or in a solution of gibberellin. They were then sown on filter paper in dishes and kept moist for 10 days. Fig. 6.2 shows the results for each group. 100 group C 1000 mg dm–3 gibberellin solution 90 80
(A/s) Accounting Oct/Nov 2010 paper 4 variant 1
Mark scheme found on page 4 / 5 pages total, pdf
Page 4 3 Mark Scheme: Teachers’ version GCE A/AS LEVEL – October/November 2010 Syllabus 9706 Paper 41 (a) $ Revenue working 1 1 715 610 purchase cost (200 000) (1) salary (30 000 + 36 000 + 43 200 + 51 840 + 62 208) rent (3600 + 3600 +
(A/s) Biology May/June 2019 paper 1 variant 2
Question paper found on page 2 / 20 pages total, pdf
2 1 The actual length of a cell structure is 8 µm. Which steps are used to calculate the magnification of an electron micrograph of this cell structure? 2 measure the length of the cell structure image on the micrograph in centimetres step 2measure the length of the cell structure image on the micrograph in millimetres step 3divide the image length by 1000 step 4multiply the image length by 100
(A/s) Biology May/June 2005 paper 6
Question paper found on page 12 / 36 pages total, pdf
12 9700/06/M/J/05 OPTION 2 – MICROBIOLOGY AND BIOTECHNOLOGY 1 (a) (i) Describe the organisation of the genetic material inside bacterial cells. .........................................................................................
(A/s) Biology Oct/Nov 2017 paper 4 variant 3
Question paper found on page 8 / 24 pages total, pdf
8 (c) Table 2.1 shows the results of the experiment. Table 2.1 colour of filter wavelength of light / nm time taken to decolourise DCPIP / s rate of light dependent stage of photosynthesis / s –1 purple 425 37 27.0 blue 450 84 11.9 green 525 480 2.1 orange 625 45 red 675 50 (i) 20.0
(A/s) Biology Oct/Nov 2017 paper 4 variant 2
Question paper found on page 5 / 24 pages total, pdf
5 (ii) using a buffer solution ........................................................................................................................................
(IGCSE) Computer Science Oct/Nov 2015 paper 1 variant 3
Mark scheme found on page 5 / 9 pages total, pdf
Page 5 Mark Scheme Cambridge IGCSE – October/November 2015 Syllabus 0478 Paper 13 (ii) MAR 1 0 0 0 1 1 1 0 MDR 0 1 1 1 1 0 0 1 [2] (iii) Address 1000 0000 1000 0001 1000 0010 1000 0011 1000 1100 1000 1101 1000
(A/s) Biology May/June 2022 paper 4 variant 1
Question paper found on page 18 / 24 pages total, pdf
18 8 (a) Over the past 200 years, many species of animals and plants have become extinct. Fig. 8.1 shows the changes between the years 1800 and 2000 in: • the number of species becoming extinct • the size of the world human population. 40 000 8000 7000 30 000 6000 5000 number of known extinct species
(A/s) Biology Oct/Nov 2002 paper 1
Question paper found on page 3 / 16 pages total, pdf
3 9700/1/O/N/02 [Turn over 4 F reshly cut potato chips are immersed for 30 minutes in four sucrose solutions of varying water potentials. The graph shows the percentage change in their length. What is the water potential of the potato cells in the freshly cut chips? A 0 kPa B – 525 kPa C – 875 kPa D – 2500 kPa 5 F
(A/s) Biology Oct/Nov 2020 paper 4 variant 3
Question paper found on page 21 / 28 pages total, pdf
21 8 Palm oil is a vegetable oil that is used very widely in food products. The oil is extracted from the fruit of the oil palm tree. (a) Oil palm trees have a higher oil yield than that of other oil-producing plants. Fig. 8.1 shows the oil yield of four crop plants. 5000 4000 3000 oil yield / kg ha–1 yr–1 2
(A/s) Biology Oct/Nov 2020 paper 4 variant 1
Question paper found on page 21 / 28 pages total, pdf
21 8 Palm oil is a vegetable oil that is used very widely in food products. The oil is extracted from the fruit of the oil palm tree. (a) Oil palm trees have a higher oil yield than that of other oil-producing plants. Fig. 8.1 shows the oil yield of four crop plants. 5000 4000 3000 oil yield / kg ha–1 yr–1 2
(A/s) Biology Oct/Nov 2015 paper 2 variant 1
Question paper found on page 10 / 16 pages total, pdf
10 9700/21/O/N/15 © UCLES 2015 (b) A student investigated the rates of transpiration and absorption of water by two species of plants, P and Q , over an 18 hour period between 0600 and 2400. The environmental conditions for the two species were the same. The results are shown in Fig. 4.2. 0600 0800 100
(A/s) Biology May/June 2017 paper 5 variant 2
Question paper found on page 11 / 12 pages total, pdf
11 (b) Over the period of the study, it was found that 8 out of every 50 voles in this population had black fur, whilst all the other voles had brown fur. Fur colour in voles is controlled by a single gene, A/a. Voles with black fur have the genotype aa. The Hardy-Weinberg principle states that: p + q = 1 p 2 + 2pq + q
(IGCSE) Geography May/June 2015 paper 1 variant 2
Question paper found on page 22 / 28 pages total, pdf
22 QUESTION 6 6 (a) Study Figs 10A, 10B and 10C, which show information about Sri Lanka (an LEDC). Relief Average annual rainfall (mm) N N 1000 1500 8° N 8° N INDIAN OCEAN INDIAN OCEAN 1000 1500 2000 2500 1500 1000 0 50 0 km 50 km 6° N 6° N
(IGCSE) Accounting Oct/Nov 2008 paper 1
Question paper found on page 5 / 12 pages total, pdf
5 © UCLES 2008 0452/01/O/N/08 [Turn over 13 A business buys a computer on credit from Alpha Computers for $1000. Which journal entry will record this? dr $ cr $ A Alpha Computers computer equipment 1000 1000 B computer equipment Alpha Computers 1000 1000 C computer equipment purchases 1000 1000 D purchases computer equipment
(A/s) Biology Oct/Nov 2012 paper 4 variant 2
Question paper found on page 19 / 24 pages total, pdf
19 © UCLES 2012 [Turn over 9700/42/O/N/12 For Examiner’s Use (c) Coral reefs are at risk of damage due to human activities. All the coral reefs in three regions were classified as being at low, medium or high risk of damage. Table 7.1 shows the areas of coral reef at risk of damage in these three regions. Table 7.1 region
(A/s) Biology Oct/Nov 2009 paper 4 variant 2
Question paper found on page 16 / 24 pages total, pdf
16 9700/42/O/N/09 For Examiner’s Use © UCLES 2009 8 (a) In the majority of plants the leaf is the main photosynthetic organ. List four ways in which the structure of a dicotyledonous leaf is adapted for gas exchange. 1 .................................................
(A/s) Biology Oct/Nov 2006 paper 2
Question paper found on page 7 / 16 pages total, pdf
7 9700/02/O/N/06 [Turn over For Examiner’s Use © UCLES 2006 (c) Chronic obstructive pulmonary disease (COPD) includes chronic bronchitis and emphysema. A student used the World Health Organisation database to investigate the link between cigarette smoking and deaths from COPD. Fig. 3.3 shows deaths from COPD plotted against the mean annual consumption of cigarettes in 20 countries for the period 1
(A/s) Thinking Skills May/June 2005 paper 1
Question paper found on page 23 / 32 pages total, pdf
23 A B Distance Apart (m) Distance Apart (m) 2000 2000 1000 1000 0 10 20 0 30 10 20 Time (mins) C 30 Time (mins) D Distance Apart (m) Distance Apart (m) 2000 2000 1000 1000 0 10 20 0 30 10 Time (mins) 20 30 Time (mins)
(A/s) Biology Oct/Nov 2011
Examiner report found on page 35 / 78 pages total, pdf
Cambridge International Advanced Subsidiary Level and Advanced Level 9700 Biology November 2011 Principal Examiner Report for Teachers © 2011 (ii) Candidates whose calculation had a logical, reasoned presentation gained full credit. These candidates had measured the line correctl y in mm, shown the conversion of the measurement to micrometres by multiplicatio n by 1000 and shown the division by the magnification (800). The most
(A/s) Biology Oct/Nov 2012 paper 4 variant 1
Question paper found on page 19 / 24 pages total, pdf
19 © UCLES 2012 [Turn over 9700/41/O/N/12 For Examiner’s Use (c) Coral reefs are at risk of damage due to human activities. All the coral reefs in three regions were classified as being at low, medium or high risk of damage. Table 7.1 shows the areas of coral reef at risk of damage in these three regions. Table 7.1 region
(A/s) Biology May/June 2015
Examiner report found on page 35 / 56 pages total, pdf
Cambridge International Advanced Subsidiary Level and Advanced Level 9700 Biology June 2015 Principal Examiner Report for Teachers © 2015 (b) (i) The majority of candidates stated that the micrometre is the most appropriate unit for use with the light microscope and showed 0.028 multiplied by 1000. (ii) Many candidates correctly stated the correct number of eyepiece graticule units for X within a range and
(A/s) Biology May/June 2013 paper 1 variant 1
Question paper found on page 2 / 16 pages total, pdf
2 © UCLES 2013 9700/11/M/J/13 1 Which size ranges can be viewed using a light microscope? 1 2 3 4 1 nm 100 nm 1 μ m 100 μ m1 mm A 4 only B 1 and 2 only C 2 and 3 only D 3 and 4 only 2 The diagram shows a mitochondrion drawn from an electronmicrograph. X Y The length of
(A/s) Biology May/June 2020 paper 1 variant 1
Question paper found on page 3 / 20 pages total, pdf
3 2 3 Which structures are found in typical eukaryotic cells? 170S ribosomes 280S ribosomes 3linear DNA (chromosomes) 4circular DNA A1, 2, 3 and 4 B1, 2 and 3 only C1 and 4 only D2 and 3 only A student examined a slide of human blood with a light microscope and made a careful drawing of the different cell types. The student used an eyepiece graticule
(A/s) Biology For examination from 2015
Learner guide found on page 79 / 82 pages total, pdf
Section 6: Appendices More information about the examination The command words used in biology examination papers are given in the sections that follow. It is very important that you know and understand all of them before you take your examination. You should ask your teacher to explain anything that you are unsure about. Numbers The decimal point will be placed on the line, e.g. 52.35. Numbers from 100
(A/s) Accounting Feb/March 2016 paper 2 variant 2
Mark scheme found on page 8 / 8 pages total, pdf
Page 8 Mark Scheme Cambridge International AS/A Level – March 2016 Syllabus 9706 Paper 22 (e) Answers may include: • • • continue with all three/do not cease production of X as they all make a contribution (1) towards fixed costs (1) Y has the highest contribution per unit (1) so should maximise its sales (1) X has the lowest contribution per unit (1
(IGCSE) Geography Oct/Nov 2015 paper 1 variant 2
Question paper found on page 3 / 28 pages total, pdf
3 (i) (ii) Complete Fig. 1 by shading Karnataka using the key provided. Karnataka has a population growth rate of 15.6 per 1000. [1] The following data is for Orissa: Birth rate 21 per 1000 Death rate 8.8 per 1000 Net migration 2 per 1000 Population growth rate 14.2 per 1000 Explain how the population growth rate of
(A/s) Biology Oct/Nov 2018 paper 3 variant 1
Mark scheme found on page 7 / 7 pages total, pdf
9700/31 Cambridge International AS/A Level – Mark Scheme PUBLISHED Question 2(b)(i) October/November 2018 Answer Marks mp 1 measures the line X within range and with units ; mp 2 shows measurement of X (mm) multiplied by 1000 ; mp 3 shows division by 13 ; mp 4 shows answer to correct degree of accuracy ; 2(b)(ii) mp 1 count number
(A/s) Biology May/June 2019 paper 3 variant 1
Mark scheme found on page 8 / 8 pages total, pdf
9700/31 Cambridge International AS/A Level – Mark Scheme PUBLISHED Question 2(b)(ii) May/June 2019 Answer Marks 1. correct measurement of the scale bar + units ; 5 2. correct measurement of length of line Z + units ; method Amethod Bmp 3 scale bar measurement multiplied by 1000 + divided by 273 ;mp 3 length of line Z divided by length of the
(IGCSE) Co-ordinated Sciences Oct/Nov 2019 paper 2 variant 1
Question paper found on page 11 / 16 pages total, pdf
11 31 A machine has useful output energy of 1000 J, and wasted energy of 300 J. Which expression is used to calculate the efficiency of the machine? A 300 × 100% (1000 + 300) B 300 × 100% 1000 C D (1000 − 300) 1000 × 100% 1000 × 100%
(A/s) Biology Oct/Nov 2009 paper 4 variant 2
Question paper found on page 12 / 24 pages total, pdf
12 9700/42/O/N/09 For Examiner’s Use © UCLES 2009 (ii) In vitro fertilisation (IVF) is a widely used treatment for infertility. Explain what is meant by the term in vitro fertilisation . ................................................................
(A/s) Physics Oct/Nov 2002 paper 1
Question paper found on page 12 / 20 pages total, pdf
12 9702/1/O/N/02 21 At a depth of 20 cm in a liquid of density 1800 kg m –3 , the pressure due to the liquid is p. Another liquid has a density of 1200 kg m –3 . What is the pressure due to this liquid at a depth of 60 cm? AB C 2 p D 3 p 22 Which line
(A/s) Biology May/June 2012 paper 3 variant 4
Mark scheme found on page 10 / 11 pages total, pdf
Page 10 Mark Scheme: Teachers’ version Syllabus Paper GCE AS/A LEVEL – May/June 2012 9700 34 © University of Cambridge International Examinations 2012 (a) (iii) [3] MMO collection 1 mp 1 shows at least one value for each of C , D , E , F , and G AND correct unit mm anywhere which match values; Ignore use of metres or m
(A/s) Accounting Feb/March 2016 paper 2 variant 2
Question paper found on page 17 / 20 pages total, pdf
17 (e) Discuss whether or not Lin should continue to produce all three products. Justify your answer. [4] Additional information Since preparing his budget, Lin has received two separate orders. For order 1 the customer has offered an amount in total of $10 000. For order 2 the customer has offered a price per unit for each separate product. The details are as follows: Order 1 X
(A/s) Biology Oct/Nov 2011 paper 3 variant 3
Mark scheme found on page 11 / 13 pages total, pdf
Page 11 Mark Scheme: Teachers’ version Syllabus Paper GCE AS/A LEVEL – October/November 2011 9700 33 © University of Cambridge International Examinations 2011 (ii) [3] measures line L correctly in mm; 14 or 14.5 or 15 or 15.5 or 16 or 16.5 mm ; MMO collection 1 [1] Additional guidance A 1.4 or 1.45 or
(A/s) Biology May/June 2019 paper 1 variant 1
Question paper found on page 10 / 16 pages total, pdf
10 23 Which nucleic acid bases are purines? Aadenine and cytosine Bcytosine and thymine Cguanine and adenine Duracil and cytosine 24 In a genetic engineering experiment a piece of double-stranded DNA containing 6000 nucleotides coding for a specific polypeptide is transcribed and translated. What is the total number of amino acids in this polypeptide? A 500 B 1000 C 2000 D 3000 25 Which
(IGCSE) Environmental Management Oct/Nov 2007 paper 2
Question paper found on page 2 / 20 pages total, pdf
2 1 Look at the world map which shows total population in 2004 and expected population in 2050 for five continents. Population change 2004–2050 ASIA 6000 EUROPE people NORTH AMERICA 2000 1000 0 2004 2050 2000 1000 0 5000 4000 3000 2000 1000 2004 2050 0 EUROPE
(IGCSE) Physics May/June 2015 paper 1 variant 1
Question paper found on page 4 / 20 pages total, pdf
4 5 A metal block has the dimensions shown. Its mass is 1000 g. 5 cm 10 cm 2 cm What is the density of the metal? 6 A 5 × 10 3 g / cm 1000 × 2 B 2 × 5 × 10 3 g / cm 1000 C 1000 ×